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4.905x^2-12x-30=0
a = 4.905; b = -12; c = -30;
Δ = b2-4ac
Δ = -122-4·4.905·(-30)
Δ = 732.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-\sqrt{732.6}}{2*4.905}=\frac{12-\sqrt{732.6}}{9.81} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+\sqrt{732.6}}{2*4.905}=\frac{12+\sqrt{732.6}}{9.81} $
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